8545. Multiplication table

Print an n × n multiplication table with alignment.

Input. One integer n (1 ≤ n ≤ 9).

Output. Print an n × n multiplication table, formatted as shown in the example.

Sample input	Sample output
5	1 2 3 4 5 2 4 6 8 10 3 6 9 12 15 4 8 12 16 20 5 10 15 20 25

SOLUTION

loops

Algorithm analysis

Use a nested loop to print the multiplication table.

Algorithm implementation

Read the input value n.

scanf("%d",&n);

Using a double loop, print the multiplication table. To ensure alignment, each number should occupy two positions. Use the %2d format for output.

for (i = 1; i <= n; i++)

{

for (j = 1; j <= n; j++)

printf("%2d ", i * j);

printf("\n");

}

Java implementation

import java.util.*;

public class Main

{

public static void main(String[] args)

{

Scanner con = new Scanner(System.in);

int n = con.nextInt();

int m[][] = new int[n+1][n+1];

for(int i = 1; i <= n; i++)

for(int j = 1; j <= n; j++)

m[i][j] = i * j;

for(int i = 1; i <= n; i++)

{

for(int j = 1; j <= n; j++)

System.out.printf("%2d ", m[i][j]);

System.out.println();

}

con.close();

}

}

Python implementation

Read the input value n.

n = int(input())

Using a double loop, print the multiplication table. To ensure alignment, each number should occupy two positions. Use the %2d format for output.

for x in range(1, n + 1):

for y in range(1, n + 1):

print("%2d" %(x * y), end=' ')

print()